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suppose you have a general quadratic equation in the form ax2 + bx + c = 0, then the solutions to this quadratic equation can be found by the equation x = (-b +/- (b2-4ac)1/2Answered by Antonia S. • Maths tutor2896 Views
The LNAT essay is not likely to be anything like an essay that you've written for any of your other subjects. You can't revise for it in the traditional sense. However, that does not mean that you cannot ...
x = 4sin(2y + 6)dx/dy = 4(2)cos(2y + 6)dx/dy = 8cos(2y + 6) ==> dy/dx = 1/8cos(2y + 6)sin2(2y + 6) + cos2(2y + 6) = 1cos(2y + 6) = √(1 - sin2(2y + 6))cos(2y + 6) = √(1 ...
To begin with, we will need to make a loop which iterates (loops) 10 times, which we can use the for statement for:for value in range (1,101): // do something - this is a comment Note, here we use the ran...
first recognise ‘area under’ = integrationfunction is a product so by partsset x=u; exp(-x)=dv/dx integral(udv/dx)=uv-integral(vdu/dx)du/dx =1; v=-exp(-x)ans=(x.-exp(-x))-integral(1.exp(-x)dx)ans=-x...
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