Top answers

Chemistry
All levels

Describe the process of distillation

Distillation is the process of boiling and condensing a mixture of liquids in a closed system, allowing the products to escape. This can separate products because the one with the lower boiling point will...

Answered by John A. Chemistry tutor
2457 Views

Explain why potassium is more reactive than sodium, giving the balanced chemical symbol equation for the reaction of potassium and water.

K + H2O --> KOH + H2Both potassium and sodium possess one electron in their outer shell. Both elements readily give up this unpaired electron and so for this reason are considere...

Answered by Liam F. Chemistry tutor
45408 Views

Given the following equilibrium: H2O + H2O <-> H3O+ + OH- and the Kw = 10^-14, determine the concentration of OH- species after the addition of 1 mmol of HCl to 1 L of neutral water.

As HCl is a strong acid, it will fully dissociate in water, releasing 1 mmol of H+, which will be the final concentration of protons in solution. The autoprotolysis equilibrium of water (or K

Answered by Samuel N. Chemistry tutor
1693 Views

The reversible reaction of sulfur dioxide and oxygen to form sulfur trioxide is shown below. 2SO2(g) + O2(g) 2SO3(g) An equilibrium mixture contains 2.4mol SO2, 1.2mol O2 and 0.4mol SO3. The total pressure is 250atm. What is the p(SO3)?

First step is to calculate the mole fraction of the SO3. This can be done by dividing the moles of SO3 by the total moles at equilibrium to give 0.4/4. This is then multiplied by the total pressure at equ...

Answered by Saji M. Chemistry tutor
15116 Views

Calculate the concentration in mol/dm3 of 8.0 g of sodium hydroxide (NaOH) in solution with a volume of 50 cm3. (Note Ar(Na) = 23, Ar(O) = 16, Ar(H) = 1)

Calculate Mr(NaOH): Mr(NaOH) = 23 + 16 + 1 = 40, Calculate NaOH moles: n= m/Mr, n= 8.0/40, n= 0.2 moles, Calculate NaOH concentration:(converting from cm3 to dm3 by /1000) c= n/v, c=...

Answered by Imogen C. Chemistry tutor
7923 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo
Cookie Preferences