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25 cm^3 of a solution of known 0.2M HCl is neutralised by titration by 21.5cm^3 of NaOH solution. Calculate then concentration of the NaOH solution to 3dp.

Recall n = c *(v/1000) if the volume is in Cm3.

Now, n(HCl)= 0.2 x (25.0/1000) 

n(HCl) = 5x10-3

Since the relationship stoichiometrically is 1:1 (H

WF
Answered by Will F. Chemistry tutor
2783 Views

Describe the Le Chantelier principle

If a factor affecting the position of an equlibirum is altered, the position fo equlibrium shifts to oppose the effect of the change. 

SS
Answered by Sudip S. Chemistry tutor
2581 Views

What is crude oil and how does fractional distillation work?

Crude oil is formed from detritus (dead living matter) of animal, plants and microscopic organisms under intense pressure and temperature. It is trapped under impervious rocks which stop the liquid and ga...

AH
Answered by Amelia H. Chemistry tutor
5284 Views

Butane (C4H10) is an alkane. Complete the displayed structure of butane.

      H    H  H   H

H - C - C - C - C - H      

      H    H   H   H

JM
Answered by Joseph M. Chemistry tutor
8038 Views

25.00cm3 of sodium hydroxide was pipetted into a conical flask. It was titrated against 0.10mol/dm3 hydrochloric acid. The mean volume of acid needed was 24.00cm3. Calculate the concentration of sodium hydroxide used in the titration.

First write out the chemical equation:

​​​​​​HCl + NaOH -> NaCl + H20

Next construct a table with the information we have and in wha...

MB
Answered by Matthew B. Chemistry tutor
10749 Views

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