Top answers

Further Mathematics
All levels

Evaluate (1 + i)^12

First convert to mod-arg form in order to use de Moivre's theorem. |1 + i| = (1^2 + 1^2)^1/2 = 2^1/2 arg(z) is the angle made by the vector of the complex number and the positive real axis. I world recomm...

Answered by Charlie L. Further Mathematics tutor
3754 Views

Use the geometric series e^(ix) - (1/2)e^(3ix) + (1/4)e^(5ix) - ... to find the exact value sin1 -(1/2)sin3 + (1/4)sin5 - ...

S = eix - (1/2)e3ix + (1/4)e5ix - … is an infinite geometric series, equal to a/(1 - r). a = eix and r = (1/2)e2ix thus S = eix/(1+(1/2)e...

Answered by Adam B. Further Mathematics tutor
2345 Views

find the sum of r from 0 to n of : 1/((r+1)(r+2)(r+3))

The solution like almost every Methods of Differences questions first involves putting the fraction into partial sums.At this point you would get 3 fractions which can be tricky to deal with. Following wh...

4459 Views

Using z=cos(θ)+isin(θ), find expressions for z^n-1/z^n and z^n+1/z^n

We make use of De Moivre's Theorem which states that (cos(θ)+isin(θ))^n=cos(nθ)+isin(nθ).z^n-1/z^n=cos(nθ)+ isin(nθ)-cos(-nθ)- isin(-nθ)=cos(nθ)+ isin(nθ)-cos(nθ)+ isin(nθ) (by trig relat...

Answered by Bogosi S. Further Mathematics tutor
4109 Views

Show that the points on an Argand diagram that represent the roots of ((z+1)/z)^6 = 1 lie on a straight line.

We want to simplify this equation to one that we know how to solve. If we let ((z+1)/z) = w, then we need to solve w^6 = 1, which is more familiar. Now we try to find the modulus and argument of w. w = re...

3345 Views

We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences