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Further Mathematics
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Given that xy=2 and y=3x+5, find x and y. Do not use trial and improvement.

There are a few ways of solving these simultaneous equations, but most of them involve substitution. Perhaps the most intuitive substitution to make is the second equation (y=3x+5) into the first one (xy=...

Answered by James P. Further Mathematics tutor
4199 Views

GCSE or A-level Maths: How can I find the x and y intercepts of a cubic function?

Assume we have the function:
y = x ( x2 + 8x - 9)
This function is known as a cubic function as when multiplying out the brackets, the highest function of x would be x3.Not...

Answered by Ahmed M. Further Mathematics tutor
10636 Views

Prove that the sum of squares of the first n natural numbers is n/6(n+1)(2n+1)

In order to do this we must follow the standard procedure for a proof by induction which is to first check a base case:Let n = 1, then the sum can be written as 12 = 1/6(1+1)(2+1) = 1 as requir...

Answered by Tutor156882 D. Further Mathematics tutor
4888 Views

Solve these simultaneous equations: 3xy = 1, and y = 12x + 3

From first equation: 3xy = 1 => x = 1/(3y)Substitute expression for x into second equation: y = 12x + 3 => y = 12(1/3y) + 3 = 4/y +3Multiply through by y: y2 = 4 + 3y => y2

Answered by Hallam M. Further Mathematics tutor
2071 Views

Solve the following simultanious equations: zy=28 and 2z-3y=13

zy=28 so y=28/z13=2z-3y13= 2z - (28 x 3)/z13=2z-84/zmultiply each side by z to give 13z = 2z2-84rearange for a quadratic2z2-13z-84=0solve by factorising(2z+8)(z-21/2)z= -4 0r 21/2sub...

Answered by Oliver B. Further Mathematics tutor
1945 Views

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