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Complete the square on this equation: 2x^2 + 20x + 15 = 0.

First you need to remove the coefficient on the x^2. We do this by factorising the 2x^2 + 20x and placing the 2 from the x^2 outside a set of brackets. This looks like:2(x2+10x) +15 = 0Then we ...

Answered by Robyn L. Maths tutor
2834 Views

Solve the following simultaneous equations 3x+y=11 and 2x+y=8

To solve a simultaneous equation you should number your equations and re arrange one of them to make y the subject. (You could do it the other way and find the expression for x first)3x + y = 11 [1] and 2...

Answered by Rachel A. Maths tutor
2482 Views

Integrate e^x sinx

Since we have two functions of x being multipied togrther, we have to integrate this by parts. Therefore if we say, u=sinx and v'=ex, then u'=cosx and v=ex.Applying the integration b...

Answered by Kishan P. Maths tutor
3765 Views

Solve the following equation 3(2x -1) = 4(x - 2)

Firstly, we need to identify what this question is asking us to do. Looking at the equation we can see that we have one unknown value, which is x. It is therefore the value of x which we are being asked t...

Answered by Oliver L. Maths tutor
2228 Views

Use integration by parts to integrate the following function: x.sin(7x) dx

Integration by parts follows the general form: ∫u (dv/dx) = u.v - ∫v (du/dx)Let x = uLet sin 7x = (dv/dx)∫x.sin(7x) dx = x.(-1/7)cos(7x) - ∫(-1/7)cos(7x).1 dx = (-x/7)cos(7x) + (1/49)sin(7x) + c

Answered by Ahanna N. Maths tutor
3813 Views

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