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Maths
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What is the equation of the tangent at the point (2,1) of the curve with equation x^2 + 3x + 4.

dy/dx = 2x + 3, m = dy/dx = 7 Equation of tangent is a straight line hence we use y-y1 = m(x-x1), y-1 = 7(x - 2), y = 7x - 13

BA
Answered by Bishr A. • Maths tutor
3402 Views

(3x+9) (7x+5)

21x^2 + 78x + 45

CA
Answered by Caitlin A. • Maths tutor
2794 Views

How do I find dy/dx for a given equation, once this is found how do I find the value of x such that dy/dx = 0.

From a given equation y = mx + c. Finding dy/dx allows us to see the gradient of the curve. In order to do this we can follow the formula:When y = x

SA
Answered by Sebastian A. • Maths tutor
29287 Views

Solve equation 5^(2*x) = 5^(x)+5

First lets put all terms on the LHS;52x-5x-5 = 0 (1);Now, to help us observe a pattern, put brackets on each term and separate power of x from its coefficients(5x)2...

EL
Answered by Elvis L. • Maths tutor
3669 Views

Solve for x (where 0<x<360) 2sin^2(x) - sin(x) - 1 = 0

Factorise the equation (the equation is quadratic in sin(x) )2 sin2(x) - sin(x) - 1 = 0(2sin(x) + 1)(sin(x) - 1) = 0Work out the solutions to the quadratic equation2sin(x) +1 = 0 or ...

Answered by • Maths tutor
6083 Views

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