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Using the product rule :u = x, so du/dx = 1
v = sin(x), so dv/dx = cos(x)
Therefore dy/dx = v(du/dx) + u(dv/dx) So dy/dx = sin(x) + x.cos(x)

We start by trying to find out the values of a and c using the information about the minimum point. We know we can rearrange the right hand side by completing the square: y = a(x^2 + 3x)+cy = a(x+3/2a)^2+...

When differentiating an expression of x and y we can use implicit differentiation when terms contain the y variable, recall that this is essentially differentiating the y term by y and then multiplying by...

x²>3(x+6)Firsty expand brackets --> x²>3x+18Then make one side = to 0 ---> x²-3x-18>0Solve the quadratic (x+3)(x-6)>0find the solutions when =0 x=-3 and ...

First, lets sketch a simple y=sin(x) graph between 0 and 2Pi radians.There are 4 different places a number could be put into this equation to affect the y=sin(x) graph.y=2sin(x) will stretch the graph to ...