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Why can’t you use the quadratic formula for every quadratic?

For most Quadrátics in the form of ax^2+bx+c=0there is atleast 2 solutions in most cases as the graph of the quadratic passes the x axis on most cases. But In some cases the quadratic graph doesn’t Cross ...

Answered by Carlos G. • Maths tutor

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What is the signed area between the curve y = x^2 - 4 and the x-axis?

The curve y = x^2 - 4 is a parabola that crosses the x axis at x = - 2 and x = 2, so the area that we are looking for is the area within the parabola when y <= 0 and -2<= x <= 2. So we expect ou...

Answered by • Maths tutor

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f(x)=x^2+12x+32=0, solve for x

Method 1: Quadratic formulaf(x)= ax²+bx+c, therefore a=1, b=12, c=32 - quadratic formula= (-b+/-(b²-4ac)^1/2)/2ax=(-12+(144-128)^1/2/2 = -4 or x=(-12-(144-128)

Answered by • Maths tutor

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Find the coordinates of the sationary points on the curve x^2 -xy+y^2=12

To find stationary points, we need to find dy/dx and set it equal to 0. Here we must use implicit differentiation: d/dx(x²) + d/dx(-xy) + d/dx(y²) = d/dx(12). Hence 2x - x(dy/dx) - y...

Answered by Adam B. • Maths tutor

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f(x) = x^3+2x^2-x-2 . Solve for f(x) = 0

f(x) = x³ + 2x² - x - 2 Use the factor theorem to test for f(1) = 0 f(1) = 1³ + 2*1² - 1 - 2 = 0 Therefore x = 1 is a solution and (x-1) is a factor of f(x) Now...

Answered by Elena S. • Maths tutor

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