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Draw a graph of x = (y+4)/4.

Note: There are multiple ways to do this, so find a way that works for you!Step 1: Get rid of the fraction.Step 2: Rearrange the new formula into y = mx + c.Step 3: Find the y-intercept and the x-intercep...

TN
Answered by Tarin N. Maths tutor
2832 Views

How do you solve simultaneous equation where one of them involves powers?

Example: y - 3x = 2 , x2 + y2 = 4 y= 3x + 2 x2 + (3x+2)2 = 4 10x2+ 12x + 4 = 4 10x2+12x=0 x(10x+12)=0 x=0 or x=-1.2 y=30 + 2 = 2 (0,2)...

LF
Answered by Luke F. Maths tutor
2710 Views

Show that arctan(x)+e^x+x^3=0 has a unique solution.

Since either sketching the function f(x)=arctan(x)+ex+x3 or evaluating the precise/approximated solutions of the equation would be impossible with A-level techniques, we have to come...

Answered by Maths tutor
3371 Views

A and B have coordinates (2,3) and (5,15), respectively. Together they form line l. Find the equation for the line r that goes through C(7,-2) and is perpendicular to l. Give the answer in the format of y=mx+b

To get the equation that describes l, we'll need to get the slope first: (15-3)/(5-2)=12/3=4r is perpendicular to l so it's slope is given by: -1/4To get b we calculate: -2=7*(-0.25) + b <=> b = -1/...

TD
Answered by Tutor376397 D. Maths tutor
3050 Views

Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.

y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(...

TM
Answered by Theo M. Maths tutor
3286 Views

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