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(2+3√2, 0)  and (2-3√2, 0)

(3*4)(4x+9)^(3-1)

Where 4 is the derivative of inside the brackets and 3 is the power of the brackets.

Therefore the answer is 12(4x+9)^2

(a) For part a, simply add the real terms together and the imaginary terms together. z₁+z₂ = (3+2i)+(4-i) = 7+i b).     

(b) For part b, multiply the brackets out, remembering...

First you have to identify the equation for y is a product. Then you can apply the product rule using (4x+1)^3 as one term and sin2x as the other. First you differentiate (4x+1)^3 using the chain rule. Yo...

First you need to make either the x value or the y value equal by multiplying each equation by a number.

2( 4x + 3y = 4 ) and 3( x + 2y = 2 ) which equals:

Equation 1: ( 8x + 6y = 8 ) and Eq...