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Solve the quadratic equation x^2+4x+6=0

x = (-b ± √(b²- 4ac ))/2aa=1 b=4 c=6-4 ± √(4²- 4*6) = -2 ± √(4² - 12) = -4 ± √(16- 12) = -4 ± √4 = -4 ± 2x= (-4 ± 2)/2x₁= -4 + 2 / 2 = -2/2 = -1x₂= ...

Answered by Tutor531443 D. • Maths tutor

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What are the suvat equations and how would you apply them to a question ?

the four suvat equations are:s=ut+0.5at²v²=u²+2asv=u+ats=0.5(u+v)ts=displacement u=initial velocity v=final velocity a=acceleration t=time for most suvat equations you wil...

Answered by Temi A. • Maths tutor

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Write x^2+4x-12 in the form (x+a)^2+b where a and b are constants to be determined.

This method is known as completing the square. To find the constant a, we must halve the coefficient of x, which in this case is 4. This is to compensate for the double term when expanding the brackets. S...

Answered by Priya G. • Maths tutor

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A curve (a) has equation, y = x^2 + 3x + 1. A line (b) has equation, y = 2x + 3. Show that the line and the curve intersect at 2 distinct points and find the points of intersection. Do not use a graphical method.

a) y = x² + 3x + 1b) y = 2x + 3At points of intersection (a) = (b).2x + 3 = x ² + 3x + 1Note this is a quadratic expression which will solve for 2 unique solutions, providing the dis...

Answered by Joseph C. • Maths tutor

3857 Views

Find the inverse of: f(x) = (2x + 3)/(x - 4)

To find the inverse of a function, f^-1(x):1) set f(x) as y: y = (2x + 3)/(x - 4)2) swap x and y: x = (2y + 3)/(y -4)3) solve the new equation for y: x(y -4) = 2y + 3 = xy -4x2y - xy = -4x - 3y...

Answered by Sophie I. • Maths tutor

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