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Given that the equation of the curve y=f(x) passes through the point (-1,0), find f(x) when f'(x)= 12x^2 - 8x +1

Firstly, Integrate the f'(x) equation by raising the power by 1 and then dividing by the new power and adding a constant c. This gives you f(x)=(12x^3)/3 -(8x^2)/2 + x + c Then you simplify, f(x)=4x^3 -4x...

Answered by Daniel M. • Maths tutor

12985 Views

If f(x)= ( ((x^2) +4)(x-3))/2x find f'(x)

Tackle differentiation questions in two parts: First put it into the simplest for possible for differenciation, then perform the differenciation.

So for this equation you should first expand the t...

Answered by Alex B. • Maths tutor

3313 Views

y=2x+5 and y-x=8. Find x and y.

The expression (2x+5) has the same value as y, and so we can use (2x+5) instead of y in the second equation. This means that we are now just dealing with one variable (x) instead of two (x and y). If we m...

Answered by Smriti R. • Maths tutor

10160 Views

Find the length of a side of the triangle (Pythagoras' Theorem) Two sides are of length 3cm and 4cm, find the length of the Hypotenuse.

a²= 3²= 9, b²= 4²= 16, a²+ b² = 3² + 4² = 25, c² = 25, c = 5

Answered by Andrew D. • Maths tutor

2494 Views

Mike paid a total of £4.69 for a chocolate bar, a bag of crisps and a jar of jam. The jar of jam costs £2.19. The chocolate bar costs 57 pence. How much did the bag of crisps cost?

There are two methods of solving this question. First let's look at the prices we already know. The jar of jam is £2.19, or else said 2 pounds and 19 pence. The chocolate bar is 57 pence, so not a whole p...

Answered by Daniela Z. • Maths tutor

2051 Views