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x = t^3 + t, y = t^2 +1, find dy/dx

dy/dx = dy/dt x dt/dx

x = t³ + t

dx/dt = 3t² +1

y = t² +1

dy/dt = 2t

dy/dx = 2t x (1 / (3t² +1) )

= 2t / (3t²

Answered by Sukhwinder K. • Maths tutor

5334 Views

Solve 7x - 14 = 4x + 7

Like all equations, you're going to start off by getting all the x's on the same side of the = side and all the rest on the other side. So we start off with 7x-14=4x+7. Moving the x's to one side means th...

Answered by Daan F. • Maths tutor

7765 Views

Find the value of 4a + 3b when a=2 and b=5

This question is asking us to place a number in the place of their corresponding letter, so as the letter a is attached to the number two, whenever we see the letter a in the equation we would replace it ...

Answered by Roisin M. • Maths tutor

13595 Views

Express 5cosx - 3sinx in the form Rcos(x+a).

cos(x+a)=cosxcosa-sinxsina so cosa=5 sina=3 which means tana=3/5 a=0.54 RADIANS R=sqrt(5²+3²). =sqrt(34) so sqrt(34)cos(x+0.54)

Answered by Elizabeth H. • Maths tutor

14414 Views

Simultaneously solve the equations 3x+2y=36 and 5x+4y=64

The easiest way to solve a simultaneous equation is by the method of substitution. First of all, we take the first equation, and rearrange it so that it is in terms of y. Or, in other words, rearrange it ...

Answered by Finlay S. • Maths tutor

10379 Views