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Factorise the following: 5a^3b^5-4ab^2

Step 1:-Find any common factors. Looking at this example, it becomes clear that a HCF won't be a numerical value (e.g. 4 or 5) as there are no factors which are common for both 4 and 5. Looking further, ...

Answered by Maths tutor
2364 Views

The equation of the regression line of y (retail price, £) on x (number of pages) for a set of books is y = 0.02x + 1.35. How can I use this equation?

A regression line comes from the line of best fit, y=mx+c. Given your data, you can find the line. C is the point where it crosses the y axis, and m is the slope. Here, we know that the price of a book is...

Answered by Andrew B. Maths tutor
2020 Views

Find the turning points of the equation y=4x^3-9x^2+6x?

To find the turning points, first find the first derivative of the equation by differentiating. Differentiating can be done in this equation by multiplying the number in front of the x by the power then l...

Answered by Douglas R. Maths tutor
3984 Views

complete the square by rewriting x^2+6x-15 in the form (x+p)^2-q

To complete the square the first thing you must do is divide the coefficient (number in front) x by 2 to give (x+3)^2We must then expand out (x+3)^2 which can be done by writing it as (x+3)(x+3) then usin...

Answered by Lamees A. Maths tutor
3224 Views

Particle A mass 0.4kg and B 0.3kg. They move in opposite direction and collide. Before collision, A had speed 6m/s and B had 2m/s. After collision B had 3m/s and moved in opposite direction. Find speed of A after collision with direction and Impulse on B.

-> m1u1 + m2u2 = m1v1 + m2v22.4 - 0.6 = 0.4v1 + 0.90.9 = 0.4 v1v1 = 2.25m/s (direction unchanged)-> I = mv - mu= (0.3 x 3) - (0.3 x -2)= 1.5 Ns

Answered by Samay S. Maths tutor
2656 Views

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