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how am I meant to solve sq.root(6^2+8^2) = cube.root(125a^3) when one side is squared and the other is cubed?

first of all, have a look at each side separately to see you you can cancel anything down.e.g. the square and square root can cancel out. => sq.root(62+82) = 6+8on the otherside, ...

Answered by Rosalind S. Maths tutor
5481 Views

what is the value of 27 to the power of -2/3

27-2/31/(272/3)1/(271/3)21/32= 1/9

Answered by Lakshmi R. Maths tutor
3517 Views

solve 125^(1/3)*2^(-3)

To find 1251/3 we have to solve x3 = 125 => This gives x=5 Then we have 2-3 is equal to 1/(23) => This is equal to 1/8So to answer the question we have 5*...

Answered by Robbie R. Maths tutor
3088 Views

solve x^3+2x^2+x=0

factorise x3+2x2+x=0 => x(x2+2x+1)=0 => x(x+1)(x+1)=0 => x(x+1)2=0 => This leads to x=0 and (x+1)2=0 so x=0 and x+1=0 => Giving us the...

Answered by Robbie R. Maths tutor
4180 Views

Using the sum, chain and product rules, differentiate the function f(x) = x^n +x^3 * sin(1/[3x])

The following function consists of the sum of two variables x^n and x^3 * sin(1/[3x]). Let's break the differentiation down term by term and differentiate xn first since it's the easier term. R...

Answered by Valeri S. Maths tutor
2462 Views

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