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To find the gradient of the curve at t=2 we need to find an expression for dy/dx and then substitute in for t=2. We can make use of the chain rule to find this expression because dy/dx = (dy/dt)/(dx/dt) a...
To solve the inequality, it must first be factorised. This could be done by the ‘complete the square’ method. However in this example it is more efficient to find a pair of numbers that multiply to give t...
Whenever you have a question asking you to solve an algebraic equation with only one unknown (x) you must put all 'x' terms on one side of the equation and all non-'x' terms on the other: 1. Take 2x away ...
The first thing to immediately recall is that parallel lines have the same gradient. in the equation of a line (which is expressed in the y=mx+c format), the gradient (m) is the coefficient of x. Answered by Hafsah B. • Maths tutor7567 Views
6x + 2y = -3 (1)*3 4x - 3y = 11 (2)*2 18x + 6y = -9 (1) 8x - 6y = 22 (2) (1) + (2) = 18x +8x + 6y - 6y = -9 + 22 => 26x = 13 => x = 1/2 sub x into (1) => (6 * 0.5) + 2y = -3 3 + ...
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