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Using partial fractions, find f(x) if f'(x)=5/(2x-1)(x-3)

First step: partial fractions 5/(2x-1)(x-3) 5=A(x-3)+B(2x-1) A=0 when x=3, so B=5/(2x3-1)=1 B=0 when x=1/2, so A=5/(0.5-3)=-2 So f'(x)=1/(x-3)-2/(2x-1) Second step: Integration f(x)= (integral)(1/(x-3))dx...

Answered by Jasmin F. Maths tutor
4425 Views

Calculate the gradient of this straight line

The gradient of a striaght line measures how much it changes when you move in one direction. For example when we move to the right in the x direction, the line goes down. The equation for finding the grad...

Answered by Tutor67677 D. Maths tutor
6501 Views

Solve simultaneous equations x + y = 3 and -3x + 5y = 7

The first equation can be multiplied by 3 to give 3x + 3y = 9. Then these two equations can be added by summing both left hand sides and both right hand sides to obtain the new equation 3x + 3y - 3x + 5y ...

Answered by Jonas V. Maths tutor
3246 Views

When Integrating by parts, how do you know which part to make "u" and "dv/dx"?

you need to think about how the integral will be simpliefied, basically you are trying to get to a state where only one function of x resides in the integral. so if you have an x2 sin3x dx insi...

Answered by Thomas G. Maths tutor
3098 Views

A cubic curve has equation y x3 3x2 1. (i) Use calculus to find the coordinates of the turning points on this curve. Determine the nature of these turning points.

y′=3x2 −6x

use of y′ = 0

0= 3x^2 - 6x

0= 3x(x-2)

therefore either x=0 or x=2

when x=0 y=1, when x=2 y=-3

(0, 1) or (2, −3) 

y''=6x-6

when x=0 y''=6(...

Answered by Charlotte B. Maths tutor
6675 Views

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