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Use implicit differentiation to find dy/dx of a curve with equation x^3 + yx^2 = y^2 + 1.

Begin by differentiating each term w.r.t x: d/dx(x^3) + d/dx(yx^2) = d/dx(y^2) + d/dx(1). the terms x^3 and 1 are simple enough to start of with: d/dx(x^3) = 3x^2 and d/dx(1) = 0. Next use the chain rule ...

Answered by Marlon H. Maths tutor
4185 Views

How do I expand the following equation (x+4)(x+2)

When dealing with questions to do with expanding brackets, you must multiply every term in one bracket with all the others in the second bracket. So for this question, we can see we have 4 terms in total:...

Answered by Henry M. Maths tutor
16057 Views

How do you solve simultaneous equtions?

Say you had two equtions to solve simultaneously.

Example 1: x + 5y = -7; 2x - 2y = 10

Multiply one of the equtions so that one of the variables has the same coefficient. In this example, I ...

Answered by Nurul Sofia Hannah M. Maths tutor
3016 Views

How do you solve simultaneous equations and why do you do it?

Solving simultaneous equations allows you to identify at which point on a graph two lines intersect. For example, take the straight line -x + y = 2 and parabolic curve y= x Firstly, let's re-...

Answered by Peter H. Maths tutor
3233 Views

Sketch the line y=x^2-4x+3. Be sure to clearly show all the points where the line crosses the coordinate axis and the stationary points

From the equation we can see the the line in a positive quadratic graph. In order to find the points where the line crosses the x axis we must let y=0 and solve for x. We can then use either inspection, c...

Answered by Matthew S. Maths tutor
4177 Views

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