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Solution:
We can first write down the formula for the area of a circle which is pi*(radius)^2.
The radius of the circle is half the diameter, so radius= 1/2(8)=4cm.
Therefore the are...
|Z| = sqrt(1/2^2 + (sqrt(3)/2)^2) = 1 arg(Z) = arctan((sqrt(3)/2)/(1/2)) = pi/3 Z = cos(pi/3) + jsin(pi/3) Z = e^j(pi/3) Apologies for the use of sqrt(), I have no way yet of using the symbol on my laptop...
First we must differentiate the equation with respect to x. To differentiate you must multiply the coefficient (number in front) by the power of x, then subtract 1 from the power. So here we find dy/dx = ...
(a+2)/5 = 3a+b ...first, we need to multiply both sides by 5
a + 2 = 5 (3a + b) ....to be able substract 3a from the right side we need to remove the bracket. We multiply the bracket by 5.
Using the FOIL (Firsts, Outsides, Insides, Lasts) mnemonic, you can expand these two brackets. F: 4x x 7x = 28x^2 O: 4x x -2 = -8x I: 7 x 7x = 49x L: 7 x -2 = -14 Therefore the expansion as a whole is: 28...
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