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A curve C is defined by the parametric equations x=(4-e^(2-6t))/4 , y=e^(3t)/(3t), t doesnt = 0. Find the exact value of dy/dx at the point on C where t=2/3 .

To solve this we must use the chain rule which is dy/dt * dt/dx. Firstly, we differentiate dy/dt. For this we must use the quotient rule, this gives us dy/dt=(9te^3t - 3e^3t)/9t^2. Now for dx/dt, by subst...

Answered by Lauren K. Maths tutor
5585 Views

Find the roots of the following equation: x^2 + x - 6 = 0

Student should factorise equation to (x-2)(x+3) = 0 This gives roots of 2 and -3

Answered by Adam R. Maths tutor
1765 Views

How do I solve a simultaneous equation like this: 2x-5y=3, 3x+2y=14 ?

Solving a simultaneous equation finds the point(s) where two lines on a graph intercept. Therefore, one way of solving the equations is to plot the two lines onto the same graph and find the coordinates o...

Answered by Ellie G. Maths tutor
8698 Views

Find the integral of tan^2x dx

You can not integrate tan2x but you can integrate sec2x Since sec2x = 1 + tan2x  Then tan2

Answered by Nandini P. Maths tutor
19911 Views

How do i solve two linear simultaneous equations 2x+y=7 & 3x-y=8 ?

To start with, try and spot whether or not two of the coeffecients (numbers next to the letters) are the same for either question (i.e. could be a 3x in one equation and a 3x in the other). This also work...

Answered by Tom B. Maths tutor
3720 Views

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