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The equation of a line is y=3x – x^3 a) Find the coordinates of the stationary points in this curve, stating whether they are maximum or minimum points b) Find the gradient of a tangent to that curve at the point (2,4)

a) A stationary point is any point on the curve that is flat, still, not increasing or decreasing. Another way to think of this is the gradient at a stationary point = 0

Firstly make an equation fo...

Answered by Lauren C. Maths tutor
6692 Views

Solve the inequality 5x + 3 ≤ 3x − 6

The first step that we need to take is to take all the 'x' terms to one side of the inequality. In this case, we can subtract '3x' from both sides to obtain 2x+3 ≤ -6. Then we want to take all the non- x ...

Answered by Ritvik U. Maths tutor
5360 Views

(6/x-2)-(2/x+3)=1

a) This question tests you on using fractions, brackets and quadratic equations.  We should start by trying to make it into a form we know how to deal with. This will be by the balance method. If we multi...

Answered by Benjamin V. Maths tutor
2405 Views

How would you find the Max and Min points on a graph?

Max and Mins occur where the slope of a graph equals zero. 

To find this, if we take the 1st derivative of a function and set the derivative equal to zero to solve for x. 

The values we solv...

Answered by Ellora S. Maths tutor
1375 Views

Make y the subject of the equation: t=(y+2)/(4-y)

Multiply by 4-y   => t(4-y)=y+2 Expand the brackets  => 4t-ty=y+2 Get all the y's on the same side => 4t-2=ty+y Factor out the y  => 4t-2=(t+1)y Divide by t+1  => (4t-2)/(t+1)=y

Answered by Christopher M. Maths tutor
2972 Views

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