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We need to solve this inequality to find the value that x could be greater or less than. First, we need to find the smallest positive x value, which is 3x. Then, we minus 3x from both sides, so only one s...
Note that you can not take a positive base log of a negative number. log5(x2-5) - log5(x) = 2log5(2) => log5((x2-5)/x) = log5Answered by Milan L. • Maths tutor3016 Views
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We will solve this question with the knowledge that dy/dx = u.(dv/dx) + v.(du/dx), where y=u.v We have y=e^x(3x+1)^2. First, we want to find u & v. By splitting the function, we have that u=e^x and v=...
We have 2tan(th) / (1 + tan^2(th)) = sin(2th)
We know that tan(A) = sin(A) / cos(A), and 1 + tan^2(A) = sec^2(A)
Therefore => (2sin(th) / cos(th)) / sec^2(th)
=> 2sin(th)*cos^2(...
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