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The x-intercepts are where the graph crosses the x-axis
To find the x-intercepts of an equation --> substitute in y = 0 and solve for x

The y-intercepts are where the graph crosses the y-a...

y=k/x²

yx²=k  

1*10²=k

k=100

x=1 y=100

x=2 y=25

x=5 y=4

x=10 y=1

You would first multiply the expression by (3-root(5))/(3-root(5) - which equals 1 - to get (6-2root(5))/14 which then equals 3/7 - (1/7)*root(5) and you are done.

First differentiate y with respect to x, which gives you dy/dx = 8 - 2x^-2. This needs to equal zero so equate to zero. 8-2x^-2 = 0. You can then bring the 2x^-2 to the other side giving 2x^-2=8. Dividing...

dy/dx = 24e^6x - sin(x) + 6