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find the integral of f'(x)=2x+5

f'(x)=2x+5

note that f'(x)=nx^n-1

so 2x is originally x²as this is 2x^2-1

and 5 is originally 5x^1-1

f(x)= x²+5x+c...

Answered by Zivanayi S. • Maths tutor

3090 Views

How do you factorize a quadratic equation which has a coefficient of x^2 other than 1?

Factorise 6x²+ x - 2 = 0

Firstly, multiply the coefficient of x² by the last number:

6 x -2 = -12

Answered by Aleezeh A. • Maths tutor

2588 Views

Express the polynomial x^3+x^2-14x-24 as a product of three linear factors.

Firstly, use the factor theorem to determine one factor. Substitute factors of 24 into the equation, beginning at plus or minus 1 and then increasing. The first factor found will be -2, therefore (x+2) is...

Answered by Scarlet W. • Maths tutor

14376 Views

Kenny has £3200 in a savings account. After a year, the bank pays him interest increasing his balance to £3360. What percentage rate was applied to the account?

Kenny originally had £3200 After a year, he had £3360 £3360 - £3200 = £160 160/3200 = 0.05 0.05 x 100 = 5% Therefore, a 5% interest rate was applied to Kenny's account

Answered by Megan C. • Maths tutor

4969 Views

Solve the quadratic equation x^2 - 5x - 14 = 0, using factorisation.

Using factorisation, first we would have to look at the factors that multiply to make the last term, (-14). We know that they are +/- 7 and -/+2, and +/- 14 and -/+ 1, respectively. Now we have listed the...

Answered by Mram E. • Maths tutor

7458 Views