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A small stone is projected verically upwards from a point O with a speed of 19.6ms^-1. Modeeling the stone as a particle moving freely under gravity find the time for which the stone is more than 14.6m above O

S = 14.7, U = 19.6, V =,  A = -g, T = t

using s = ut + 1/2 at^2
14.7 = 19.6t + 1/2 -g t^2
1/2 g t^2 - 19.6t + 14.7 = 0

t = (19.6 +- sqrroot(-19.6- 4 * 0.5 * 9.8 * 14...

Answered by Hamish B. Maths tutor
4289 Views

(i) Find the point(s) where the curve y=x^2-2x+1 crosses the x-axis, and (ii) find the coordinates of the vertex of the curve.

(i) Recall that a curve crosses the x-axis (the horizontal axis) when the vertical y-coordinate is zero, so we are required to find all the points such that y=0, that is we must solve the equation x2...

Answered by Ethan T. Maths tutor
8690 Views

Solve for x, 15x+8 = 53

15x + 8 = 53

15x = 53-8 = 45

x = 45/15 = 3

Answered by Sarah K. Maths tutor
4604 Views

In a sale, the original price of a bag was reduced by 1/5. The sale price of the bag is £29.40. Work out the original price.

  1. We currently have 80% of the original price and aim to find 100%.

  2. We know that 80% is equal to £29.40.

  3. Dividing £29.40 by 80 gives the value of 1% which is £0...

Answered by Oliver B. Maths tutor
12879 Views

c is a positive integer. Prove that (6c^3 + 30c) / (3c^2 +15) is an even number.

  1. We aim to factorise the numerator. This would give 6c(c^2 + 5).

  2. We then factorise the denominator. This would give 3(c^2 + 5).

  3. Since (c^2 + 5) is present in b...

Answered by Oliver B. Maths tutor
8062 Views

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