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Express 3sinx - 2cosx in the form R(sin(x-a) given R>0 and 0<a<90°. Hence solve 3sinx - 2cosx = 1 in the interval 0<x<360°. What are the maximum and minimum values of 2sinx - 3cosx?

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CC
Answered by Calem C. Maths tutor
9132 Views

There is a cube with a length 3x. The expression for the volume in cubic centimeters is equal to the expression for the surface area in square centimeters. Calculate the length of a side of the cube.

volume = SA (3x)= (3x)2 x 6 27x3 = 9x2 x 6 27x3 = 54x2 27x = 54 27x - 54 = 0 27(x - 2) = 0 x - 2 = 0 x = 2 The question asks for the len...

SD
Answered by Sofia D. Maths tutor
6473 Views

Find ∫(x^3+x^2+6)dx.

∫(x3+x2+6)dx= ∫x3dx +∫x2dx+∫6dx =x4/4 +x3/3 +6x+C.

GI
Answered by Georgiana I. Maths tutor
5767 Views

How do you 'complete the square' of a quadratic equation?

To complete the square, we need to rearrange the quadratic equation in the form of ax2 + bx + c into the form r(x + p)2 + q, where our task is to find the values of the unkowns of r,...

RB
Answered by Ryan B. Maths tutor
2765 Views

Using the trigonometric identity (sinx)^2 + (cosx)^2 = 1, show that (secx)^2 = (tanx)^2 + 1 is also a trigonometric identity.

We can divide by (cosx)^2 across the identity (sinx)^2 + (cosx)^2 = 1 (which can be derived from properties of the unit circle and a bit of Pythagoras’ theorem) to achieve

[(sinx)^2 / (cosx)^2] + [...

AB
Answered by Annie B. Maths tutor
3252 Views

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