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How do I find the roots of a quadratic equation?

A quadratic equation is an equations of the form:   ax+ bx + c = 0 (1)  where a is not 0. The ways of finding the roots are:  quadratic formula, factorising, substituting, completing the squa...

CM
Answered by Catriona M. Maths tutor
3607 Views

Solve for x: 2x+3+((4x-1)/2)=10

Solve for x: 2x+3+((4x-1)/2)=10 First of all, move all the values on the left-hand side of the equation that are not in brackets over to the right-hand side of the equation so as to make the fraction (in ...

LH
Answered by Luke H. Maths tutor
3266 Views

Integrate dy/dx = 2x/(x^2-4)

Integrate dy/dx = 2x/(x2-4).

We can answer this question using integration by substitution, where we set u = something in terms of x.

In this case we are going to set u = x2<...

WR
Answered by William R. Maths tutor
10317 Views

Solve algebraically: 6a + b = 16 5a - 2b = 19

b= 16-6a  this will be your substitution. 

5a- 2(16-6a)=19 now multiply out.

5a-32+12a=19 always remember positive and a negative multiplied is a negative.

17a=51

a= 51/17 = 3 ...

JD
Answered by Jade D. Maths tutor
2828 Views

Solve the quadratic equation x^2-6x+5=0

x2 - 6x + 5 = 0.

For simple quadratic equations such as this example we need to factorise the expression into 2 brackets: (x+a)(x+b) = 0.

To find a and b we can expand the bracket...

WR
Answered by William R. Maths tutor
8691 Views

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