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(a)STEP 1: Take out the coefficient of x^2 from the x^2 and x terms. 2(x)2+7x-3=0 2(x2+(7/2)x)-3=0STEP 2: Complete the Square by finding (b/2)2. ...
suppose you have a general quadratic equation in the form ax2 + bx + c = 0, then the solutions to this quadratic equation can be found by the equation x = (-b +/- (b2-4ac)1/2Answered by Antonia S. • Maths tutor2588 Views
x = 4sin(2y + 6)dx/dy = 4(2)cos(2y + 6)dx/dy = 8cos(2y + 6) ==> dy/dx = 1/8cos(2y + 6)sin2(2y + 6) + cos2(2y + 6) = 1cos(2y + 6) = √(1 - sin2(2y + 6))cos(2y + 6) = √(1 ...
first recognise ‘area under’ = integrationfunction is a product so by partsset x=u; exp(-x)=dv/dx integral(udv/dx)=uv-integral(vdu/dx)du/dx =1; v=-exp(-x)ans=(x.-exp(-x))-integral(1.exp(-x)dx)ans=-x...
2 Secx = 2/CosxCotx = 1/Tan x = Cosx/SinxTherefore: 2SecCotx = 2/Cosx * Cosx/Sinx = 2/Sinx = 2Cosecx
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