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Equations: (1) x^2-y=16 and (2) 2y-4=14xRearrange (2) to give y:2y-4=14x(+4) 2y=14x+4(/2) y=7x+2call the new equation (3) y=7x+2Put (3) into (1):x^2-(7x+2)=16(expand) x^2-7x-2=16(-16) x^2-7x-18=0(Factoris...

I would require to demonstrate most of this working and explaining on a white, as a keyboard can not allow a lot of the mathematical notation required to solve this, but once I have a white board I ...

To rationalise the denominator without chainging the value of the equation, multiply both the numerator and denominator by the value of the denominator.( (5+√2)/(√3) )*(√3/√3) = ( (5√3)+√6 )/3

Looking for a combination of numbers that would multiply to give (-12_ but add together to give (-1)e.g. -6, 2?....-2,6....-4,3 = yes!thus,(y-4)(y+3)

This is how the answer would be written in an exam!5x - 7 = 3x + 35x-3x = 3 + 72x = 10 x = 10/2x = 5