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We first multiply both sides of the equation by (3y+4) to get x(3y+4)=2y+1. We then expand the left hand side to get 3xy+4x=2y+1. By rearranging the equation we get 3xy-2y=1-4x. We then factorise the left...

First we need to draw our two brackets where the terms will go, we set them out like so ( )( ). Now looking at the coefficient of the x squared term, we se that it is one, therefore, it is formed by a mul...

A quadratic equation ax² +bx+c=0 will have only one unique solution if and only if b²-4ac=0. If we apply this to the equation in the question, we get that k²-24=0. If we s...

So, students should be able to solve basic linear equations as shown above. The aim in order to solve the equation would be to get all of the x values onto one side of the equation and all of the integers...

2x + y = 6x - y = 6x = 6 + y => 2(6 + y) + y = 18 => 12 + 3y = 18 => 3y = 6 => y = 2x - (2) = 6 => x = 8x = 8, y = 2