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We are given y as a function of x, let's first compute dy/dx, and then solve the equation dy/dx =0. dy/dx = 9 -1/x2. Then dy/dx = 0 is equivalent to 9 = 1/x2. Taking x2 on...
QUOTIENT RULE: [u(x) / v(x)]' = [u'(x)v(x) - u(x)v'(x)] / v2We have: u(x) = x4 - 1, hence u'(x) = 4x3v(x) = x4 + 1, hence v'(x) = 4x3So we have: [(4x...
For this question it is key to remember the indices laws. The ones you need to recall for this question are: xa / xb = xa - b, and (xa)b = xa * ...
= We start by halfing the 10 and putting x + 5 in a bracket = (x + 5)^2 = Opening these brackets give us x^2 + 10x + 25 = To make the 25 the same as - 3 we have to minus 28 = Therefore the answer is = (x ...
dy/dx = 4x - 12 x-coordinate= 5 so sub in 20-12 = 8
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