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Find (dy/dx) of x^3 - x + y^3 = 6 + 2y^2 in terms of x and y

In order to differentiate this expression, we need to use implicit differentiation. An expression in the form y = f(x), where f(x) means "a function of x", is called an explicit equation and nee...

Answered by Maths tutor
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If x^2-5x+6=0, solve for x.

Since x^2-5x+6=0 is a quadratic we need to factorize before solvingAll quadratics fall under this formula ax^2+bx+c=0 so in this case a=1, b=-5 and c=6Drawing the very common ac b table we get: ac|b ...

ME
Answered by Matthew E. Maths tutor
3020 Views

The straight line joining the points (1, -2a),(a, 1) has a gradient of 5, find the value of a

m=y-y1/x-x15=1-(-2a)/a-15=1+2a/a-15(a-1)=1+2a5a-5=1+2a3a=6a=2

TB
Answered by Theo B. Maths tutor
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Differentiate y=x^2 from first principles

y=x2dy/dx= Limh-->0( ((x+h)2-x2) / (x+h-x) )dy/dx= Limh-->0( (x2 + 2hx + h2 - x2) / h )dy/dx= Limh-->0...

DC
Answered by Dipayan C. Maths tutor
5400 Views

How to find the turning point on a curve?

The equation of the curve will be a quadratic i.e. it follows the form y=ax2+bx+cTo find the turning point, the quadratic will need to be solved using the completing the square method. This me...

MV
Answered by Muhammad V. Maths tutor
3939 Views

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