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Find the two real roots of the equation x^4 - 5 = 4x^2 . Give the roots in an exact form. [4]

x⁴ - 5 = 4x². In order to find the roots of this equation we must factorise it, and, to do so, it must be rearranged such that all the terms are on one side. Therefore, subtract 4x

Answered by Sanjay S. • Maths tutor

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ABC is an isosceles triangle such that AB = AC A has coordinates (4, 37) B and C lie on the line with equation 3y = 2x + 12 Find an equation of the line of symmetry of triangle ABC. Give your answer in the form px + qy = r where p, q and are integers (5

As we know that AC = AB, then it must be the case that BC is the base of the triangle (because it is isosceles). Therefore, the line of symmetry of the triangle ABC goes through the point A, and is perpen...

Answered by Sanjay S. • Maths tutor

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Convert 0.22222222... (recurring) into a fraction

x=0.22222222...10x= 2.222222...10x-x=9x=2x=2/9=0.2222222...
x=2/9

Answered by Rachel G. • Maths tutor

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Solve the equation log2(x + 3) + log2(x - 3) = 4

log2(x + 3) + log2(x - 3) = 4log2 [(x + 3)(x - 3)] = 4x^2 - 9 = 16x^2 = 25x = 5

Answered by • Maths tutor

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Work out the gradient and y-intercept of the straight line with points A(3,8) and B(-2,-7)

Y= mx + cFinding m : change in y/ change in x => (8--7)/(3--2) = 3Finding c : input a pair of coordinates => 8 = (3 x 3) + c .... c = -1y = 3x -1

Answered by Kim R. • Maths tutor

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