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y = 1/x^2 is the same asy = x^-2 , now we can use the standard differentiation formula nx^n-1 to gety = -2x^-3y = -2/x^3

To solve using elimination, you need to use the following four steps:Step 1: make sure that both of the equations have opposite x terms or opposite y terms. Currently neither of the x terms in the two equ...

1. the x squared is counted as A, the 6x is counted as B and -10 is C2) you halve the B term so in this case it would be 3x from the 6x and write it with an x in a bracket squared e.g. (x+3)^23) then y...

The first step of solving simultaneous equations with two unknown variables (m & n in this case) is to rearrange one of the equations so that we get one variable in terms of the other. Lets take the f...

This is a typical question for a Core 1 paper. (a) integral of y = (-2)x^(-1/2) + 0.1x^5 + 2x +C Method: Increase the power of x by +1, divide the term through by the new power. (b) dy/dx = (-3/2)x^(-5/2)...