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Find the equation of the tangent line to the curve y = 2x^2 - 4x + 3 at the point (3,9)

To find the equation of the tangent line to the curve y = 2x2 - 4x + 3, we have to differentiate. Taking each part of the equation separately, we can calculate dy/dx = 4x - 4. By differentiatin...

Answered by Maths tutor
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y = 1/x^2, differentiate y (taken from AQA 2018 past paper)

y = 1/x^2 is the same asy = x^-2 , now we can use the standard differentiation formula nx^n-1 to gety = -2x^-3y = -2/x^3

Answered by Maths tutor
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Solve this simultaneous equation using the process of elimination: -6x - 2y = 14 3x - 2y = 5

To solve using elimination, you need to use the following four steps:Step 1: make sure that both of the equations have opposite x terms or opposite y terms. Currently neither of the x terms in the two equ...

Answered by Emily B. Maths tutor
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How do you complete the square for the question x^2 + 6x - 10 ?

  1. the x squared is counted as A, the 6x is counted as B and -10 is C2) you halve the B term so in this case it would be 3x from the 6x and write it with an x in a bracket squared e.g. (x+3)^23) then y...
Answered by Amelia S. Maths tutor
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Solve algebraically the simultaneous equations: 6m + n = 16 and 5m - 2n = 19

The first step of solving simultaneous equations with two unknown variables (m & n in this case) is to rearrange one of the equations so that we get one variable in terms of the other. Lets take the f...

Answered by Harry D. Maths tutor
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