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First solve complementary function, i.e. d²x/dt² + 5dx/dt + 6x = 0. To do so, let x = e^mt, where m = arbitrary constant. Differentiating gives dx/dt = m e^mt and...

y=(x²-1)(x³+3) ...

given u = cos(x), therefore du/dx=-sin(x), as tan(x)=sin(x)/cos(x), can rewrite tan(x)=(-du/dx)/u, therefore integral can become [(-1/u)du], after inegrating you are left with -ln(u)+c, therefore ln(1/u)+...

Therefore, y = x^xcan then natural log both sides leaving ln(y) = xln(x) then differentiating both sides wrst to x d/dx(ln(y)=xln(x))we are then left with this expression (dy/dx)(1/y)=ln(x)+1 mu...

Resolving all forces in the vertical gives the normal force as 10gcos(30). Resolving all forces normal to the slope gives the frictional force as 2gcos(30) (given Friction = mu*R). Using second law, F=ma....