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The equation of line 1 is: 3y-5x+3=0. The equation of line 2 is : y= 5x/3+9. Check whether the 2 lines intercept.

Rearranging the first equation: 3y=5x-3Then dividing by 3 so that the equation of the line will become in the form of y=mx+c, where m is the gradient and c is the interception point with the y-axis (0,c)W...

Answered by Panagiotis G. • Maths tutor

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Expand the brackets in the following expression and indicate what the graph would look like: y=(5x+1)(2x-3)

While this question is not in the style the examiners would ask, it demonstrates two important principles: how to expand brackets accurately and how to build intuition about the shape of graphs.
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Answered by Edward E. • Maths tutor

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Find X log(x)=4 Base 10

Log base 10log(x)=4 ~ 10⁴=xx=10000

Answered by • Maths tutor

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Solve the simultaneous equations y+4x+1 = 0 and y^2+5x^2+2x = 0

x = -1/3 and y = 1/3 or x = -1/7 and y = -3/7

Answered by Mustafa Q. • Maths tutor

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Prove that 1 + tan^2 x = sec^2 x

We know that tan x = sin x/cos x and so tan²x = sin²x/cos²x. We also know that sin²x + cos²x = 1 because this is a Pythagorean identity. We can rewri...

Answered by Eleanor F. • Maths tutor

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