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The sides of an equilateral triangle are given by the expressions x+y, 2y-1 and 3y-2x+1. Find the values of x and y.

This question test knowledge of the geometry of equilateral triangles and the students ability to solve linear equations.
First we note that an equilateral triangle has equal sides. Then we can write...

Answered by Joe S. Maths tutor
6588 Views

Factorise fully 2x^2 -x -4=2 and thus solve for x

Recall that to solve a quadratic it needs to be in the form ax2 + bx +c = 0, Subtract 2 from each side to get 2x2-x-6=0 therefore a=2 b=-1 and c=-6 Solve by considering factors c and...

Answered by Lucy S. Maths tutor
2240 Views

A = {multiples of 5 between 14 and 26}. B = {odd numbers between 14 and 26}. List the members of A∪B and A∩B.

First write down explicitly what the elements of A and B are.A={15,20,25}, B={15,17,19,21,23,25}.
Remember ∪ means OR. So A ∪ B is the set of items which are in either A OR B. This is {15,17,19,21,23...

Answered by Luke P. Maths tutor
13577 Views

∫2x(x+2)^(1/2) dx evaluated from 0->2

First make a substitution so we can apply the power rule ∫xn dx = (xn+1)/(n+1) + C more simply. Can see u=x+2 means (x+2)1/2 -> u1/2 and so will help us appl...

Answered by Luke P. Maths tutor
10231 Views

Please expand the following brackets: (x+3)(x+5). Give your answer in its simplest form.

So how I would start to solve this problem is by using a method called the claw method (because it looks like a claw).So in order to expand the brackets, we need to multiply each term in the first bracket...

Answered by Clarence L. Maths tutor
3183 Views

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