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A straight line passes through the point (0, 6) and is perpendicular to y = 4x - 5. Find the equation of this line, giving your answer in the form y = mx + c .

perpendicular so the gradient is -1/4
y= -1/4x +CSub in the coordinate (0,6)
6 = -1/4 (0) +C
C=6y=-1/4x +6

Answered by Maria S. Maths tutor
7030 Views

factorise x^2 - 8x -65

Two numbers add/ subtract to make -8Two numbers multiply to make -65. These are 1 and 65 as well as 5 and 13Seeing as 1 and 65 cant add or subtract to make -8 the numbers we'll use are 5 and 13. These als...

Answered by Kavi C. Maths tutor
4240 Views

The normal to the curve C when x=1 intersects the curve at point P. If C is given by f(x)=2x^2+5x-3, find the coordinates of P

Differentiate C:dy/dx=4x+5When x=1dy/dx=4(1)+5dy/dx=9This is gradient of tangent.Gradient of normal=-1/9When x=1, y=4y-4=-1/9(x-1)y=(-1/9)x+(37/9)(-1/9)x+(37/9)=2x^2+5x-30=2x^2+(46/9)x-(64/9)x=1 or x=-32/...

Answered by Hannah C. Maths tutor
3069 Views

Differentiate 3x^2 + 4x - 7

In order to differentiate a number, 2 steps are needed to be made. The first is to reduce the power of the number by 1 and then multiply that value to the first number. I will run you through the given qu...

Answered by James R. Maths tutor
4399 Views

Find the positive solution to the equation (x^2+9x+18)/(x^2-9)=10

If we first factorise the top and the bottom of the equation we can see that the top is equal to (x+6)(x+3) and the bottom is (x-3)(x+3). This means we can divide the top and bottom by (x+3) giving us a r...

Answered by Joseph R. Maths tutor
2589 Views

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