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For a graph C with equation y=3/(5-3x)^2, find the the equation of the line normal to the graph at point P, where x=2. Give your answer in the form ax+by+c=0

Find out the value of the y coordinate where x=2y=3/(5-3(2))^2=3Differentiate function in order to find the gradient of the graph at point Py=3/(5-3x)^-2Use chain rule where u=5-3xdu/dx=-3dy/dx=3u^-2Hence...

Answered by Jazib I. • Maths tutor

3342 Views

3 teas and 2 coffees have a total cost of £7.80 5 teas and 4 coffees have a total cost of £14.20 Work out the cost of one tea and the cost of one coffee.

3t + 2c = 7.80 ---> x2 to get 6t + 4c = 15.605t + 4c = 14.20 6t + 4c = 15.60-- 5t + 4c = 14.20= 1t = 1.40If t = 1.40 substitute t in to the equation to get:(3 x 1.40) + 2c = 7.80 ---> 2c = 3.60 --&g...

Answered by Hania K. • Maths tutor

2058 Views

Solve the following equation: x^2 - 5x - 14 = 0

The equation above is an example of a quadratic. The easiest way of solving this is to split the equation into two brackets, allowing you to equal each individual bracket to zero, and so get a value of x....

Answered by Noah N. • Maths tutor

2368 Views

What are radians, why can't we just use degrees?

When you start your A Level, radians can seem very daunting because you've never seen them before and pi seems a very confusing number to use in relation to angles. But trust me, if you embrace radians th...

Answered by Matthew R. • Maths tutor

2529 Views

The Volume of a tin of radius r cm is given by V=pi*(40r-r^2-r^3). Find the positive value of r for which dV/dr=0 and find the value of V for this r.

Firstly differentiate the function V with respect to x (dV/dx)=pi*(40-2r-3r^2). Set dV/dr =0 and solve to find r. Divide both sides by pi and divide both side by -1 so that the r^2 term is positive (I per...

Answered by Chorley K. • Maths tutor

3690 Views