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Solve (x+10)(x-16)=0

x+10=0x= -10x-16=0x= 16

Answered by Sophie T. Maths tutor
2558 Views

(x+3)(x-4)(x+5) is identical to x^3 +ax^2 -17x+b. Find the value of a and the value of b.

Multiplying out the first two brackets gives (x^2-x-12)(x+5). Multiplying the remaining brackets gives x^3 + 4x^2 -17x - 60.

a = 4b = 60

Answered by Aeron E. Maths tutor
7338 Views

Solve the simultaneous equations : x ^2+2y=9, y=x+3 to find solutions for x and y.

We must use the substitution method for this question because the first equation is a quadratic. Take the more simple equation (the second one), and use that to substitute the value for y in to the first ...

Answered by Callum R. Maths tutor
2593 Views

Find out the stationary points of the function f(x)=x^2*e^(-2x)

Using the product rule (u'v+v'u, where u and v are the chosen substitutes) to find the first derivative will be dy/dx=x'=2xe^(-2x)+x^(2)e^(-2x)(-2)=2xe^(-2x)(x-x^2). This will give the d...

Answered by Bilkan I. Maths tutor
2692 Views

Solve the simultaneous equations: 2x+y=18 and x-y=6

To solve these simultaneous equations there are two different methods that could be used. The first one to try in this case is to start with rearranging one of the equations to get a value of y by itself....

Answered by Ella E. Maths tutor
3323 Views

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