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Given that y = 5, solve the following equation for x, 9x - 3y = 97 - 5x

Subsitute y for 5 to give 9x - (3 * 5) = 97 - 5xCalculate the brackets 9x - 15 = 97 - 5xAdd 15 to both sides 9x = 112 - 5xAdd 5x to both sides 14x = 112Divide both sides by 14 x = 8

Answered by Frank D. • Maths tutor

2803 Views

Solve for x, 4x+3.5 = 1

First, you regroup all numbers which are not factors of x on one side of the equation:
4x = 1 - 3.5
so 4x = - 2.5
Then, you isolate x:
x = - 2.5/4
x = - 5/8 = - 0.625

Answered by Jade S. • Maths tutor

2483 Views

A particle is in equilibrium under the action of four horizontal forces of magnitudes 5 newtons acting vertically upwards ,8 newtons acting 30 degrees from the horizontal towards the left,P newtons acting vertically downwards and Q newtons acting to right

first of all we need the resolve the diagonal force into its horizontal and vertical components. Using trigonometry you can deduce that the horizontal component equates to 8Cos30 and the vertical componen...

Answered by Ali A. • Maths tutor

5184 Views

Solve algebraically the simultaneous equations: x^2 + y^2 = 25, y - 3x = 13

Steps:Number both equationsUsing equation 2, solve for y in terms of x.Substitute this answer into equation 1 so that your equation only includes x terms and no y terms.Solve equation 1 for x. (This will ...

Answered by Rowena M. • Maths tutor

1806 Views

A cricket player is capable of throwing a ball at velocity v. Neglecting air resistance, what angle from the horizontal should they throw at to achieve maximum distance before contact with the ground? How far is that distance?

Assume angle of throw theta. Resolving vertical and horizontal components: Vvert=v.sin(theta) and Vhoriz=v.cos(theta).From 'suvat' equations, time to vertical stationary t=v/a. This must be doubled to fin...

Answered by Benjamin W. • Maths tutor

2734 Views