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The curve C has equation y = x^3 - 3x^2 - 9x + 14. Find the co-ordinates and nature of each of the stationery points of C.

Step 1: Differentiate y with respect to x. dy/dx = 3x^2 - 6x - 9
Step 2: Equate to zero and solve. 3x^2 - 6x - 9 = 0(x - 3)(x+1) = 0x = 3, x = -1
Step 3: Substitute into original equation to fin...

Answered by Daniel A. Maths tutor
3972 Views

Solve algebraically the simultaneous equations, giving your answers in terms of b : 3x+by=5, x-y=-2

First, I would label the two equations 1 and 2:(1) 3x+by=5(2)x-y=-2Next, multiply (2) by 3 and subtract this equation from (1) in order to cancel out the x terms: 3x+by=5-(3x-3y=-6)This results in the equ...

Answered by Thomas L. Maths tutor
2711 Views

A straight line goes through the point (7, 5) with a slope of 2. What is the equation of the line?

Th equation of a line is denoted as y = mx + c, with m as the slope and c as the y intercept. We already know that the slope is 2. Since the line passes through the point (7, 5)...

Answered by Caitlin C. Maths tutor
4795 Views

Differentiate 8x^3+4x^2+2

24x^2+8x

Answered by Maximilian B. Maths tutor
2880 Views

Simplify- (8/27)^(2/3)

We know that (8/27)^(1/3). = (2/3)Then do (2/3)^2 = (4/9)Split up 2/3, into powers of 1/3, and 2.

Answered by Theo M. Maths tutor
4444 Views

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