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A car is accelerating at 2 ms^-2 along a horizontal road. It passes a point A with a velocity of 10 ms^-1 and later a point B, where AB = 50m. FInd the velocity of the car as it passes through B.

From the first look, we can see the question states the car is undergoing constant acceleration, thus we know the SUVAT equations are valid. Then reading on, we're required to find the final velocity, v, ...

Answered by Maths tutor
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find the gradient of y=x3 X0=5

dx/dy = 3(x)2substitute x = 5so (5) squared 253 times 25 = 75

Answered by Jenna A. Maths tutor
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Use these 2 simultaneous equations to find x & y: 5y+21=9x and 6x+7y=45

Okay so first, to make the process more simple, I would suggest collecting all algebraic terms on the same side of the question as to get: 9x-5y=21 and 7y+6x=45 (as it already is). Next, looking at both e...

Answered by Maddy S. Maths tutor
1990 Views

The curve C has equation: 2x^2y + 2x + 4y – cos (piy) = 17. Use implicit differentiation to find dy/dx in terms of x and y.

You want to take the derivative of both sides of the equation with respect to x which produces an equation in terms of x, y and dy/dx which can then be rearanged. The right side is just 0 since 17 is a co...

Answered by Maths tutor
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What is algebra and why do we use it?

Algebra is a part of mathematics in which letters or symbols are used to represent either a known constant or an unknown value. Algebra is often used within formulae in which we can extrapolate an answer,...

Answered by Maths tutor
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