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Solve the following simultaneous equations: x^2 + y^2 = 29 and y - x =3

This question is slightly trickier than normal simultaneous equations, because we have values to the power of 2. What we can do is make either y or x the subject of the 2nd equation (y-x = 3). For this ex...

Answered by Trushna D. Maths tutor
3150 Views

Using the binomial theorem, find the coefficient of x^4*y^5 in (x-2y)^9.

The term containing x4y5 will be C(9, 5)x4(-2y)5 = (9!/(5!4!))x4(-2)5y5The coefficient of which will be 1...

Answered by George H. Maths tutor
3024 Views

There are 48 girls in a large cheerleading squad. The ratio of girls to boys in this squad is 8:3. How many boys are in the squad?

There are (48/8)*3=18 boys. Since the ratio of boys to girls is 8:3 you divide the number of girls by 8 which gives 6 and then multiply by 3 to give the number of boys.

Answered by George H. Maths tutor
2360 Views

In a group of 120 people, 85 have black hair, 78 have brown eyes and 20 have neither black hair nor brown eyes. Find the probability of a random person being picked having black hair, given they have brown eyes

We are told that the person already has brown eyes, and this includes 78 people.We are asked to find the probability of them also having black hair.This means the person has to have brown eyes and black h...

Answered by Daniel C. Maths tutor
2548 Views

Using the trigonometric identity for tan(A + B), prove that tan(3x)=(3tan(x)-tan^3(x))/(1-3tan^2(x))

tan(3x)=tan(2x+x), by using the identity for tan(A+B)=(tan(A)+tan(B))/(1-tan(A)tan(B)),tan(3x)=tan(2x+x)=(tan(2x)+tan(x))/(1-tan(2x)tan(x)), using it again for tan(2x),tan(3x)=tan(2x+x)=([(tan(x)+tan(x))/...

Answered by Ivan R. Maths tutor
8610 Views

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