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Find the equation of the tangent to the curve y=3x^3+x^2+5 at the point (1,9)

y=11x-2

Answered by Ethan W. Maths tutor
3083 Views

y=x^3-3x^2+2x+5 a)Write down the coordinates of P the point where the curve crosses the x-axis. b)Determine the equation of the tangent to the curve at P. c)Find the coordinates of Q, the point where this tangent meets the curve again.

a) P (0,5)b) y = 2x + 5c) Q (3,11)

Answered by Harrison A. Maths tutor
3993 Views

Five Chocolate bars cost £11. Three Chocolate Bars and two packs of Biscuits cost £13.6. How much does two Chocolate bars and one pack of biscuits cost.

We know from the question that 5C = £11, where C is number of Chocolate Bars. Therefore C= 11/5 which is £2.20.We also know that 3C + 2B = £13.6 where B is number of packs of Biscuits.Since we know what C...

Answered by Samuel S. Maths tutor
3649 Views

Differentiate: y = 3x^2 + 4x + 1 -4x^-1

dy/dx = 6x +4 +4x-2

Answered by Harry F. Maths tutor
2702 Views

Solve y=x^2 - 1, y=5 - x

x= -3, y= 8 and x= 2, y= 3
(1) 5 - x = x^2 - 1(2) x^2 + x - 6 = 0(3) (x+3)(x-2) = 0(4) when x = -3, y= 5 - (-3) = 8(5) when x = 2, y= 5 -(2) = 3

Answered by Tamim B. Maths tutor
2769 Views

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