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How do I apply the correct formulae and other methods to difficult looking questions?

The trick here is to figure out what topic the question relates to, and recall all relevant theory and formula. Often questions look tougher than they actually are. Begin by writing out what you know at t...

Answered by Ollie S. Maths tutor
2485 Views

show y=3x-5 is tangent to x^2 + y^2 +2x -4y - 5 = 0 and the point where they touch

y=3x-5x^2 + (3x-5)^2 + 2x - 4(3x-5) - 5 = 0x^2 + 9x^2 -30x +25 + 2x -12x + 20 - 5 = 010x^2 -40x + 40 = 010 (x^2 - 4x +4) = 010(x - 2)^2 = 0x=2implies one point of contact, therefore tangenty = 3x - 5y = 6...

Answered by Robert M. Maths tutor
2004 Views

I struggle with long worded questions

Ok let’s take this example:5 tins of soup have a total weight of 1750 grams. 4 tins of soup and 3 packets of soup have a total weight of 1490 grams. Work out the total weight of 3 tins of soup and 2 packe...

Answered by Idris K. Maths tutor
2652 Views

Find dy/dx when y = 4x^1/2

dy/dx means you have to differentiate the equation provided: y = 4x1/2When we differentiate with respect to x we must multiply the power by the coefficient: 1/2 = power by 4 = coefficient which...

Answered by Christopher B. Maths tutor
8610 Views

The equation of the line L1 is y = 3x – 2 The equation of the line L2 is 3y – 9x + 5 = 0 Show that these two lines are parallel

L1 ->  y = 3x – 2L2 -> 3y – 9x + 5 = 0
L2 3y = 9x − 5 L1 3y = 9x -6
Gradient is the same therefore lines are parallel.

Answered by Mark S. Maths tutor
2429 Views

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