Equation: x2 +4x-5=0 (This is in the form ax2+2bx+c=0)First divide 2b by 2 (4/2=2)Then put this into (x+b)2-(b)2+c=0This gives: (x+2)2-(2)2
dy/dx = 20 - 2x - 6x2 = -6x2 - 2x + 20 which factorises to dy/dx = (10 - 6x)(2 + x). This shows that x=-2 and x=10/6=5/3 are stationary points of y = 20x −x2 −2x3