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Expand and simplify (x − 4)(2x + 3y)^2

You should start off by separating the brackets as the squared only applies to one of them. We'll deal with that one first. Write the (2x + 3y)^2 as two separate brackets of (2x+3y). Then multiply the fir...

Answered by Lois B. Maths tutor
3967 Views

Factorise and solve x^2 - 8x + 15 = 0

Look for factors of 15 then when adding together equal -8. A solution to this is -5 and -3 as -5 x -3=15 and (-5)+(-3)=-8 . Therefore the factors of the quadratic are (x-5) and (x-3). Make (x-5)(x-3)=0 so...

Answered by Amrit S. Maths tutor
2701 Views

What is the easiest way to solve a simultaneous equation?

While the elimination method can be extremely easy for certain questions, it cannot be applied to all. Therefore, the substitution method is recommended because it can be applied to most cases of simultan...

Answered by William A. Maths tutor
2450 Views

Factorise fully 12x^2-20x+3

By factorising we're attempting to simplify this expression. When we factorise quadratics, typically this will result in two brackets. The content of these brackets, can be simply worked out with trial ...

Answered by Santiago O. Maths tutor
3809 Views

What are the two roots of the equation y=x^2+5x+6?

A root of a function is where the function equals zero. So to begin to solve we must set the function to equal zero.x^2-5x+6 = 0If the question didn't make it clear already, you should be able to identif...

Answered by Niamh M. Maths tutor
3165 Views

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