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Given point A: (5,9), point B: (d,15) and the gradient of line AB is 3... what is the value of d?

First use the gradient equation for a line: difference in y over difference in x:dy/dx = gradienttherefore: (15-9)/(d-5) = 315-9=3(d-5)6=3d-1521=3dtherefore d = 7

Answered by James C. Maths tutor
2485 Views

Solve the simultaneous equations: 5x + y = 21, x - 3y = 9

Call '5x + y = 21' equation 1 and 'x - 3y = 9' equation 2. To solve this, we need the coefficients of x in both equations to be the same or the coefficients of y in both equations to be the same.
Met...

Answered by Basil I. Maths tutor
4039 Views

Solve the equation 2(3x-5)=7

Firstly expand the brackets due to BIDMAS.6x-10=7Now we want to have x on its own side, so add 10 to both sides.6x=17Finally we want to solve to find x, so divide both sides by 6.x=17/6

Answered by Will B. Maths tutor
1521 Views

Factorise 3x+12

We should start by looking for the highest common factor of the 2 numbers involved in the equation (3&12)If you cannot do this immediately in your head, create a factor tree or list the factors3: 312:...

Answered by Ellis T. Maths tutor
8083 Views

solve the simultaneous equation x^2 + 2y = 9 , y - x = 3

First we need to find a value for x in terms of y , this can be done by rearranging the second equation y - x = 3 to give x = y - 3. This equation is then substituted into the first equation so tha...

Answered by Sara B. Maths tutor
2315 Views

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